1.

The short weve length limit for the Lyman series of the hydrogen spectrum is `913.4 Å` Calculate the short wevelength limit for Balmer series of the hydrogen spectrum.

Answer» Using `(1)/(lambda) = R ((1)/(n_(i)^(2)) - (1)/(n_(i)^(2)))` Here, `n_(i) = 1, n_(f) = 2 ` for short weve
`(1)/(lambda) = R((1)/(1^(2)) - (1)/(2^(2)) ) rArr lambda = (4)/(3lambda) ` …(i)
Also, for Balmer short weve length, `n_(1) = 2, n_(f) = 3`
`(1)/(lambda) = R((1)/(1^(2)) - (1)/(2^(2)) ) = (R5)/(36) rArr lambda = (36)/(5R)`
Using `lambda = (36)/(5xx4) xx3 xxlamda = (27xx913.4)/(5) = 4932.36Å`.


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