1.

The shortest distance between the curves y = |x^(2) – 6x – 27| and (x – 3)^(2) + (y – 39)^(2) = 4 is

Answer»


Solution :`y - |x^(2) - 6x - 27|`
`=|(x - 9) (x -3)|`
`y(3) = |(-6)6| = 36`
`(x - 3)^(2) + (y - 39)^(2) = 4`
CENTRE `x = 3, y = 39 & R = 2`.
Shortest distance will be along x = 3,
Shortest distance = `(39 - 2) - 36 = 1`.


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