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The shortest distance between the curves y = |x^(2) – 6x – 27| and (x – 3)^(2) + (y – 39)^(2) = 4 is |
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Answer» `=|(x - 9) (x -3)|` `y(3) = |(-6)6| = 36` `(x - 3)^(2) + (y - 39)^(2) = 4` CENTRE `x = 3, y = 39 & R = 2`. Shortest distance will be along x = 3, Shortest distance = `(39 - 2) - 36 = 1`. |
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