The shortest distance between the skew lines `bar(r) = bar(a_(1)) + lambda bar(b_(1)) "and" bar(r) = bar(a_(2)) + mu bar(b_(2))` isA. `d=|((b_(1)-b_(2)).(a_(1)xxa_2))/(a_(1)xxa_(2))|`B. `d=|((b_(1).b_(2)).(a_(1)-a_2))/(|b_(1)||b_2|)|`C. `d=|((b_(1)xxb_(2)).(a_(2)-a_1))/(|b_(1)|xx|b_2|)|`D. `d=|((b_(1)xxb_(2)).(a_(2)xxa_1))/(|b_(1)xxb_2||a_1xxb_2)|`

The shortest distance between the skew lines `bar(r) = bar(a_(1)) + la

1.	The shortest distance between the skew lines `bar(r) = bar(a_(1)) + lambda bar(b_(1)) "and" bar(r) = bar(a_(2)) + mu bar(b_(2))` isA. `d=\|((b_(1)-b_(2)).(a_(1)xxa_2))/(a_(1)xxa_(2))\|`B. `d=\|((b_(1).b_(2)).(a_(1)-a_2))/(\|b_(1)\|\|b_2\|)\|`C. `d=\|((b_(1)xxb_(2)).(a_(2)-a_1))/(\|b_(1)\|xx\|b_2\|)\|`D. `d=\|((b_(1)xxb_(2)).(a_(2)xxa_1))/(\|b_(1)xxb_2\|\|a_1xxb_2)\|`
Answer» Correct Answer - C `therefore ` The shortest distance between two skew lines is `d=\|((b_(1) xxb_(2)).(a_(1)xxa_(1)))/(\|b_(1) xx b_(2)\|)\|`

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