1.

The shortest distance between the skew lines r = (6hati + 2hatj + 2hatk) + t(hati - 2hatj + 2hatk) and r= ( -4hati - hatk ) + s(3hati - 2hatj - 2hatk) is

Answer»

9
`40/7`
108
120

Answer :A


Discussion

No Comment Found

Related InterviewSolutions