1.

The shortest distance from (1,1,1) to the line of intersection of the pair of planes xy+yz+zx+y^(2)=0 is

Answer»

`sqrt(8/3)`
`2/sqrt(3)`
`1/sqrt(3)`
`2/3`

Solution :`xy+yz+y^(2)=0`
`RARR y(x+y)+z(x+y)=0`
`rArr` Line of intersection is `x=-y=z`.
Distance of OP on line having direction RATIOS 1,-1 is `1/sqrt(3)`.
Then required shortest distance `=sqrt(3-1/3)=sqrt(8/3)`.


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