The shortest wavelength of the Brackett series of a hydrogen-like atom – InterviewSolution

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1.	The shortest wavelength of the Brackett series of a hydrogen-like atom (atomic number of `Z` ) is the same as the shortest wavelength of the Balmer series of hydrogen atom. The value of `z` isA. 3B. 4C. 5D. 2
Answer» Correct Answer - D According to the question, `" " lambda_(("shortest"))"Brackett"=(lambda_("shortest"))"Balmer"`" `rArr" "(1)/((lambda_("shortest"))"Brackett")=(1)/((lambda_("shortest"))"Balmer")` `rArrZ^(2)R((1)/(4^(2)))=R((1)/(4))rArrZ^(2)=4 rArrZ=2`

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