The shortest wavelength of transition in Paschen series of `He^(+)` ion in nanometer (nm) is `(1/(R_(H))=91.12nm)`.

The shortest wavelength of transition in Paschen series of `He^(+)` io

1.	The shortest wavelength of transition in Paschen series of `He^(+)` ion in nanometer (nm) is `(1/(R_(H))=91.12nm)`.
Answer» Correct Answer - `205.02` For shortest wavelength `n_(2)=oo` `1/(lamda_("min"))=4xxR_(H)[1/(3^(2))-1/(oo^(2))]` ltrbgt `1/(lamda_("min"))=4/9 R_(H)` `lamda_("min")=9/4xx1/(R_(H))nm` `=205.02nm`

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The shortest wavelength of transition in Paschen series of `He^(+)` ion in nanometer (nm) is `(1/(R_(H))=91.12nm)`.

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