The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q and then parallelogram PBQR is completed (see Fig. 9.26). Show that ar (ABCD) = ar (PBQR).

The side AB of a parallelogram ABCD is produced to any point P. A line

1.	The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q and then parallelogram PBQR is completed (see Fig. 9.26). Show that ar (ABCD) = ar (PBQR).
Answer» The side $A B$ of a parallelogram $A B C D$ is produced to any point $P$ . A line through $A$ and parallel to $C P$ meets $C B$ produced at $Q$ and then parallelogram $P B Q R$ is completed (see Fig. 9.26). Show that ar $(A B C D)$ $=$ ar $(P B Q R)$ .