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The side of a square is increasing at the rate of 0.2 cm/s. The rate of increase of perimeter w.r.t time is :A. 0.2 cm/sB. 0.4 cm/sC. 0.6 cm/sD. 0.8 cm/s |
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Answer» Correct Answer - 4 If side =a, then rate of increase of perpendicular w.r.t time `= 4((da)/(dt)) = 4(0.2) = 0.8` cm/s |
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