The side of a square is increasing at the rate of 0.2 cm/s. Find the r

1.	The side of a square is increasing at the rate of 0.2 cm/s. Find the rate of increase of the perimeter of the square.
Answer» Consider the side of a square as a It is given that the rate of change of side is da/dt = 0.2 cm/s We know that the perimeter of a square = 4a So the rate of change of perimeter is 4 da/dt = 4 × 0.2 We get dP/dt = 0.8 cm/s

The side of a square is increasing at the rate of 0.2 cm/s. Find the rate of increase of the perimeter of the square.

Answer»

Consider the side of a square as a

It is given that the rate of change of side is

da/dt = 0.2 cm/s

We know that the perimeter of a square = 4a

So the rate of change of perimeter is

4 da/dt = 4 × 0.2

We get

dP/dt = 0.8 cm/s