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The side of a square is increasing at ther rate of `0.2 cm//s`. The rate of increase of perimeter w.r.t. time is :A. 0.2 cm/sB. 0.4 cm/sC. 0.6 cm/sD. 0.8 cm/s |
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Answer» Correct Answer - D If side=a then rate of increase of perimeter w.r.t. time `-4((da)/(dt))-4(0.2)=0.8cm//s` |
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