The side of square is 39 cm. If the side of square is doubled to form

1.	The side of square is 39 cm. If the side of square is doubled to form length of rectangle, what would be the width of rectangle to keep the area of rectangle equal to the area of square?1. 13 cm2. 20 cm3. 19.5 cm4. 26 cm
Answer» Correct Answer - Option 3 : 19.5 cm Given: Side of square = 39 cm Length of rectangle = 2 × side of square Concepts used: Area of square = (Side)² Area of rectangle = Length × Width Calculation: Area of square = (Side)² ⇒ (39)²= 1521 cm². Length of rectangle = 2 × side of square ⇒ 2 × 39 cm ⇒ 78 cm. Area of rectangle = Length × Width As area of rectangle is to be kept equal to area of square, ⇒ 1521 = 78 × width ⇒ Width = 1521/78 ⇒ Width = 19.5 cm. ∴ The width of the rectangle is equal to 19.5 cm.

The side of square is 39 cm. If the side of square is doubled to form length of rectangle, what would be the width of rectangle to keep the area of rectangle equal to the area of square?1. 13 cm2. 20 cm3. 19.5 cm4. 26 cm

Answer» Correct Answer - Option 3 : 19.5 cm

Given:

Side of square = 39 cm

Length of rectangle = 2 × side of square

Concepts used:

Area of square = (Side)²

Area of rectangle = Length × Width

Calculation:

Area of square = (Side)²

⇒ (39)²= 1521 cm².

Length of rectangle = 2 × side of square

⇒ 2 × 39 cm

⇒ 78 cm.

Area of rectangle = Length × Width

As area of rectangle is to be kept equal to area of square,

⇒ 1521 = 78 × width

⇒ Width = 1521/78

⇒ Width = 19.5 cm.

∴ The width of the rectangle is equal to 19.5 cm.

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