1.

The sides of a square are x=4, x=7, y=1, y=4. Then theequation of the circumcircle of the square is

Answer»

`X^(2)+y^(2)-11x-5y+32=0`
`x^(2)+y^(2)-11x-5y+7=0`
`x^(2)+y^(2)-6x-5y+7=0`
`x^(2)+y^(2)-5x-2y+15=0`

ANSWER :A


Discussion

No Comment Found

Related InterviewSolutions