The simplest aromatic hydrocarbon C_6H_6 reacts B on treatment with sodium hydroxide will (C_6H_5OH), Phenol, C as the product. Also Cl_2 to give A which on reaction with sodium hydroxide gives B. B of molecular formula C_6H_6O. B on treatment with ammonia will give C_6H_7N as D. Identify A, B, C and explain the reactions involved.

The simplest aromatic hydrocarbon C_6H_6 reacts B on treatment with so

1.	The simplest aromatic hydrocarbon C_6H_6 reacts B on treatment with sodium hydroxide will (C_6H_5OH), Phenol, C as the product. Also Cl_2 to give A which on reaction with sodium hydroxide gives B. B of molecular formula C_6H_6O. B on treatment with ammonia will give C_6H_7N as D. Identify A, B, C and explain the reactions involved.
Answer» Solution :(i) The aromatic hydrocarbon A is Benzene, `C_6H_6`. (II) Chlorobenzene B reacts with SODIUM hydroxide to give `(C_6H_5OH)` phenol, C as the product `underset("Benezene A")(C_6H_6 + Cl_2) overset(FeCl_3)to underset("Chloro benzene B")(C_6H_5Cl) + HCl` (ii) Chlorobenzene B reacts with sodium hydroxide to give `(C_6H_5OH)` phenol, C as the product. `underset(R)(C_6H_5Cl_2) + NAOH underset(300atm)overset(350^@C)to underset("PhenolC")(C_6H_5OH + NaCl)` (IV) Chlorobenzene reacts with ammonia to give Aniline, `C_6H_5NH_2` D as the product. `C_6H_5Cl + 2NH_3 underset(50 atm) overset(250^@C)to underset("Aniline D")(C_6H_5NH_2) + NH_4Cl`