The simulaneous solubility of AgCN (Ksp = 2.5 xx 10^(-16)) and AgCl (Ksp = 1.6 xx 10^(-10)) in 1.0 M NH_(3(aq)) are respectively (K_(f)[Ag(NH_(3))_(2)]^(+) = 10^(7))

The simulaneous solubility of AgCN (Ksp = 2.5 xx 10^(-16)) and AgCl (K

1.	The simulaneous solubility of AgCN (Ksp = 2.5 xx 10^(-16)) and AgCl (Ksp = 1.6 xx 10^(-10)) in 1.0 M NH_(3(aq)) are respectively (K_(f)[Ag(NH_(3))_(2)]^(+) = 10^(7))
Answer» `0.037, 5.78 xx 10^(-8)` `5.78 xx 10^(-8), 0.037` `0.04, 6.258 xx 10^(-8)` `1.58 xx 10^(-3), 1.26 xx 10^(-5)` Solution :`underset((s))(AGCL)+underset((aq))(2NH_(3))hArr [AG(underset((aq))(NH_(3)))_(2)]^(+) + underset((aq))(Cl)^(-)` `K_(1) = 1.6 xx 10^(-10) xx 10^(7)` `= 1.6 xx 10^(-3)` `= ([Ag(NH_(3))_(2)]^(+)[Cl^(-)])/([NH_(3)]^(2))` `AgCH_((s))+2NH_(3(aq)) hArr[Ag(NH_(3))_(2)]_((aq))^(+) + CN_(aq)^(o.)` `K_(2) = 2.5 x 10^(-16) xx 10^(7) = 2.5 xx 10^(-9)` `= ([Ag(NH_(3))_(2)]^(+)[CN^(-)])/([NH_(3)]^(2))` `([Cl^(-)])/([CN^(-)]) = (1.6 xx 10^(-3))/(2.5 xx 10^(-9)) = 6.4 xx 10^(5)` `K_(1) = (x^(2))/((1-2x)^(2))` `(x)/(1-2x) = 0.04` `x = 0.037` `[CN^(-)] = (0.037)/(6.4 xx 10^(5)) = 5.78 xx 10^(-8) M`