InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
The size of isoelectronic species — F – , Ne and Na+ is affected by (a) Nuclear charge (Z ) (b) Valence principal quantum number (n) (c) Electron-electron interaction in the outer orbitals (d) None of the factors because their size is the same. |
|
Answer» The size of an isoelectronic species increases with a decrease in the nuclear charge (Z). For example, the order of the increasing nuclear charge of F– , Ne, and Na+ is as follows: F – < Ne < Na+ Z 9 10 11 Therefore, the order of the increasing size of F– , Ne and Na+ is as follows: Na+ < Ne < F– |
|