1.

The sketeton equation to represent the action of chlorine on a hot solution of sodium hydroxide is : NaOH+Cl_(2)rarr NaCl+NaClO_(3)+H_(2)O Balance this equation by the method of partial Equations.

Answer»

Solution :This reaction is supposed to take place in the following steps:
(i) Chlorine reacts with water to form hydrochloric acid and HYPOCHLOROUS acid as intermediate products.
`Cl_(2)+H_(2)Orarr HCl+HClO"…(1)"`
(ii) Sodium hydroxide neutralises the acids formed in STEP (i) to form the corresponding salts
`NaOH+HClrarr NaCl+H_(2)O"...(2)"`
`NaOH+HClOrarr NaClO+H_(2)O"...(3)"`
(iii) Sodium HYPOCHLORITE, NaClO, is unstable at higher temperature. It undergoes self oxidation REDUCTION to give a mixture of sodium chloride and sodium chlorate.
`3NaClOrarr 2NaCl+NaClO_(3)"...(4)"`
(iv) To cancel the intermediate products which do not OCCUR in the final equation, multiply the partial equations (1), (2) and (3) by 3 each and then add all the four equations. We get
`3Cl_(2)+6NaOHrarr 5NaCl+NaClO_(3)+3H_(2)O`
This represents the balanced chemical equation.


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