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The sky wave with a frequency of 20 MHz is incidnet on D-region at an angle of `45^(@)`, then angle of refraction isA. `12.5^(@)`B. `15^(@)`C. `30^(@)`D. `45^(@)` |
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Answer» For D-region, `N=10^(9)m^(-3)` Refractive index of a layer of atmosphere is `mu=[1-(81.45N)/(v^(2))]^(1//2)=[1-(81.45xx10^(9))/((20xx10^(9))^(2))]^(1//2)` approx 1` `mu=(sin i)/(sin r)approx1` or `sin r=sin i-=sin 45^(@)` or `r=45^(@)` |
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