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The sleeper density of a broad gauge track is (M + 7) in metric units, where M is length of rail in metres. The number of sleepers for 1.024 km length of track is:1. 17002. 15003. 16004. 1900 |
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Answer» Correct Answer - Option 3 : 1600 On Indian railways standard length of BG rail = 13 m So, total no. of rail required in 1.024 km or 1024 m = 1024/13 = 78.78 = 80 (in round figure) Sleeper density = M + 7 M = length of rail So, sleeper density = 13 + 7 = 20 No. of sleepers = 20 × 80 = 1600 |
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