The slope of the tangent to the curve x=t2+3t−8,y=2t2−2t−5 at th – InterviewSolution

1.	The slope of the tangent to the curve x=t2+3t−8,y=2t2−2t−5 at the point (2,−1) is
Answer» The slope of the tangent to the curve $x = t^{2} + 3 t - 8, y = 2 t^{2} - 2 t - 5$ at the point $(2, - 1)$ is

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