1.

The solubility of a salt of weak acid (AB) at pH 3 is Y xx 10^(-3) mol L^(-1). The value of Y is ___________ (Given that the value of solubility product of AB(K_(sp)) = 2 xx 10^(-10) and the value of ionization constant of HB(K_(a)) = 1 xx 10^(-8))

Answer»


Solution :`S = sqrt(K_(SP)(([H^(+)])/(K_(a))+1))= sqrt(2 xx10^(-10)((10^(-3))/(10^(-8))+1)) = sqrt(2 xx 10^(-5))`
`= 4.47 xx 10^(-3) M`


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