The solubility of AgCl is 1.435xx10^(-5) gL^(-1) at 30^@C temp. then calculate its solubility product .

The solubility of AgCl is 1.435xx10^(-5) gL^(-1) at 30^@C temp. then c

1.	The solubility of AgCl is 1.435xx10^(-5) gL^(-1) at 30^@C temp. then calculate its solubility product .
Answer» SOLUTION :`1.0xx10^(-14)`