The solubility of AgCl(s) with solubility product 1.6 xx 10^(-10) in 0.1 M NaCl solution would be

The solubility of AgCl(s) with solubility product 1.6 xx 10^(-10) in 0

1.	The solubility of AgCl(s) with solubility product 1.6 xx 10^(-10) in 0.1 M NaCl solution would be
Answer» `1.6xx10^(-11)` M 0 `1.26xx10^(-5)` M `1.6xx10^(-9)` M Solution :`{:(NaCl to , NA^(+) + , Cl^-),(0.1M, 0,0),(0,0.1 M, 0.1 +S):}` `{:(AgCl hArr , Ag^(+)+, Cl^-),(0.1 M, 0,0),(x-S,S,S+0.1):}` `K_(SP)=1.6xx10^(-10) = [Ag^+][Ci]=[S]` [S+0.1] `because K_(sp)` is small , S is neglected with respect to 0.1 M `1.6xx10^(-10) =Sxx0.1` `S=1.6xx10^(-9)` M