1.

The solubility of AgCl (s) with solubility product `1.6xx10^(-10)` in 0.1 M NaCl solution would beA. `1.26xx10^(-5) M`B. `1.6xx10^(-9) M`C. `1.6xx10^(-11)M`D. zero

Answer» Correct Answer - B
`{:(AgCl(s),overset(+aq)hArr ,Ag^(+)(aq),+,Cl^(-)(aq)),(S,,S,,S+0.M"(from NaCl)"),(,,,,~=0.1M (" as " S lt lt 0.1)):}`
`K_(sp)=[Ag^(+)][Cl^(-)]`
`1.6xx10^(-10)=S(0.1) "or" S=1.6xx10^(-9)M`


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