

InterviewSolution
Saved Bookmarks
1. |
The solubility of AgCl (s) with solubility product `1.6xx10^(-10)` in 0.1 M NaCl solution would beA. `1.26xx10^(-5) M`B. `1.6xx10^(-9) M`C. `1.6xx10^(-11)M`D. zero |
Answer» Correct Answer - B `{:(AgCl(s),overset(+aq)hArr ,Ag^(+)(aq),+,Cl^(-)(aq)),(S,,S,,S+0.M"(from NaCl)"),(,,,,~=0.1M (" as " S lt lt 0.1)):}` `K_(sp)=[Ag^(+)][Cl^(-)]` `1.6xx10^(-10)=S(0.1) "or" S=1.6xx10^(-9)M` |
|