1.

The solubility of Ba_3(AsO_4)_2(formula weight=690 )is 6.9 xx 10^(-2)g//100 ml. what is the K_(sp)?

Answer»

`1.08 xx 10^(-11)`
` 1.08 xx 10^(-13)`
` 1.0 xx 10^(-15)`
` 6.0 xx 10^(-13)`

Solution :`S= 6.9 xx 10^(-2)gm // 100ml `
` =(6.9xx10 ^(-2))/( 690 )mol //100 ML `
` = 10 ^(-4)" mole " //100ml `
`therefore 100ml -10 ^(-4)"mole " `
` 100 ml -10 ^(-4)" mole " `
`rArr 10 ^(-3)" moles" rArr K_(Sp) =108 S^(5) `


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