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The solubility of BaSO_4 is 5 mol L^(-1) then what is the solubility product ? |
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Answer» Solution :`{:(BaSO_(4(s)) hArr, Ba_((aq))^(2+) +, SO_(4)^(2-)),(,SM, SM):}` `K_(sp)=[Ba^(2+)][SO_4^(2-)]=(S)(S)=S^2` `=(5)^2=25 ("MOL L"^(-1))^2` |
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