The solubility of BaSO_4in water is 2.42 xx 10^(-3) gL^(-1)at 298 K. The value of its solubility product (Ksp) will be (Given molar mass of BaSO_4 = 233 g "mol"^(-1))

The solubility of BaSO_4in water is 2.42 xx 10^(-3) gL^(-1)at 298 K. T

1.	The solubility of BaSO_4in water is 2.42 xx 10^(-3) gL^(-1)at 298 K. The value of its solubility product (Ksp) will be (Given molar mass of BaSO_4 = 233 g "mol"^(-1))
Answer» `1.08 xx 10^(-8) "mol"^2 L^(-2)` `1.08 xx 10^(-10) "mol"^2 L^(-2)` `1.08 xx 10^(-14) "mol"^2 L^(-2)` `1.08 xx 10^(-12) "mol"^2 L^(-2)` Solution :SOLUBILITY of `BaSO_4 ("mol" L^(-1) ) = (2.42 xx 10^(-3))/(233) = S` `K_(sp) " of " BaSO_4 = (s)^2` ` = ((2.42 xx 10^(-3))^2)/(233))` ` = 1.078 xx 10^(-10) "mol"^2 L^(-2)` `1.08 xx 10^(-10) "mol"^2 L`