1.

The solubility of CaF_(2) is 2xx10^(-4) mole /litre . Its solubility product is

Answer»

`2.0 xx 10^(-4)`
` 4.0 xx 10 ^(-8) `
` 4 xx 8.0 xx 10 ^(-12) `
` 3.2 xx 10^(-4)`

Solution :`S= 2 xx 10 ^(-4) , M`
` K_(Sp) = 4S^(3) =4 xx (2xx 10 ^(-4))^(3) =32 xx 10 ^(-12) `


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