1.

The solubility of [Co(NH)_(3))_(4)Cl_(4)]CIO_(4)____if the lambda_(Co(NH_(3))_(4)Cl_(2)^(+)=50, lambda_(ClO_(4)^(-)=70 and the measured resistance was 35.5 Omega in a cell with cell constant of 0.20 is ____

Answer»

59.75 mmol/L
49.75 mmol/L
39.75 mmol/L
29.75 mmol/L

Solution :`lambda_([CO(NH_3)_4Cl_2]ClO_4)^@=lambda_([CO(NH_3)_4Cl_2^(-)])^@ .^(+LAMBDA^@)[ClO_4^(-)]=50+70=120`
`lambda_([CO(NH_3)_4Cl_2]ClO_4)=(1000 K)/M`
`K=G SIGMA`
=1/33.5x0.20
`lambda_([CO(NH_3)_4Cl_2]ClO_4)=120xx(1000xx0.20)/(33.5xxM)`
`M=(1000xx0.20)/(33.5xx120)=49.75` mmol/L


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