1.

The solubility of N_(2) in watcr at 300 K and 500 torr partial pressure is 0.01 g L ^(-1). The solubility (in g L ^(-1)) at 750 torr partial pressure is :

Answer»

`0.0075`
`0.005`
`0.02`
`0.015`

Solution :ACCORDING to Henery law
`(P_(1))/(P _(2)). (S_(1))/(S_(2))`
`(500)/( 750) . (0.01)/( S_(2))`
`. S_(2). (750*0.01)/( 500) . 0.015 g //L`


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