1.

The solubility of PbCl_(2) is

Answer»

`sqrt(K_(SP))`
`3sqrt(K_(sp))`
`3sqrt((K_(sp))/(4))`
`sqrt(8K_(sp))`

Solution :`{:(PbCl_(2) hArr,Pb^(2+),+,2CL^(-)),(,S,,S):}`
`K_(sp)` of `PbCl_(2) = [Pb^(2+)] xx [Cl^(-)]^(2) , K_(sp) = S xx (2S)^(2)`
`K_(sp) S xx 4S^(2) = 4S^(3), S^(3) = (K_(sp))/(4) , S = 3sqrt((K_(sp))/(4))`


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