1.

The solubility of silver chromate in 0.01 M K_(2)CrO_(4) is 2 xx 10^(-8) mol m^(-3). The solublity product of silver chromate will be

Answer»

`8 xx 10^(-24)`
`16 xx 10^(-24)`
`1.6 xx 10^(-18)`
`16 xx 10^(-18)`

Solution : `{:("Given " K_(2)CrO_(4),hArr,2K^(+),+,CrO_(4)^(2-)),("CONC. "0.01,,0.02,,0.01),("and for "Ag_(2)CrO_(4),,,,):}`
`{:(Ag_(2)CrO_(4),hArr,2Ag^(+)+,CrO_(4)^(2-)),(S,,2S,S+0.1):}`
`K_(SP) = [Ag^(+)][CrO_(4)^(2-)]`
`K_(sp) = (2S)^(2)(S + 0.01) rArr 4S^(2) [S + 0.01]`
? `K_(sp) = 4[2 xx 10^(-8)]^(2) xx 0.01 [[2 xx 10^(-8)]^(2) lt lt 0.01]`
`K_(sp) = 4 xx 4 xx 0.01 xx 10^(-16), K_(sp) = 16 xx 10^(-18)`


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