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The solubility of Sr (OH)_(2) at 298K is 19.23 g/L of solution. Calculate the concentrations of strontium and hydroxyl ions and the pH of the solution. (Atomic mass of Sr = 87.6) |
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Answer» Solution :Molar MASS of Sr `(OH)_(2) = 87.6+34=121.6 g "MOL" ^(-1)` Solubility of Sr `(OH)_(2) ` in moles `L^(-1)=(19.23g L^(-1))/(121.6g "mol"^(-1))=0.1581M` Assuming complete DISSOCIATION , Sr`(OH)_(2)rarrSr^(2)+2OH^(-)` `:. [Sr^(2+)]=0.1581 M, [OH^(-)]=2xx0.1581=0.3162`M `pOH=-log 0.3162=0.5, :. pH = 14-0.5=13.5` |
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