1.

The solubility product for SrF_(2) is 7.9xx10^(-11). A solution is 0.01 M in NaF. The minimum concentration of SrCl_(2) in the solution required to start the precipitation of SrF_(2) is equal to :

Answer»

`0.89xx10^(-5)`M
`0.79xx10^(-6)` M
`0.79xx10^(-8)` M
`0.89xx10^(-7)` M

Answer :B


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