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The solubility product of a sparingly soluble metal hydroxide M (OH)_(2) at 298 K is 5xx10^(-16)"mol"^(3)"dm"^(-9). The pH value of its queous and saturated solution is |
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Answer» 5 `K_(sp)=(s) (2s)^(2)=4S^(3)` `s^(3)=(K_(sp))/(4)=(5xx10^(-16))/(4)=1.25xx10^(-16)` `=125xx10^(-18)` `:. S=5xx10^(-6)M, i.e., [OH^(-)]2xx5xx10^(-6)M` `=10^(-5)M` pOH = 5.0 pH=14-5 = 9 |
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