1.

The solubility product of a sparingly soluble salt AX_(2) is 3.2 xx 10^(-11). Its solubility (in moles/litres) is

Answer»

`2 XX 10^(-4)`
`4 xx 10^(-4)`
`5.6 xx 10^(-6)`
`3.1 xx 10^(-4)`

SOLUTION :`AX_(2) rarr UNDERSET(x)(A) + underset(2X)(2X)`
`K_(sp) = 4 x^(3), x = 3sqrt((3.2 xx 10^(-11))/(4)), x = 2 xx 10^(-4)` mole/litre


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