1.

The solubility product of Ag_(2)CrO_(4) is 32 xx 10^(-12). What is the concentration of CrO_(4)^(-) ions in that solution

Answer»

`2 xx 10^(-4) M`
`16 xx 10^(-4) M`
`8 xx 10^(-4) M`
`8 xx 10^(-8) M`

Solution :`UNDERSET(S)(Ag_(2)CrO_(4)) rarr underset(2S)(2Ag^(+)) + underset(S)(CrO_(4)^(--))`
`K_(sp) = (2S)^(2)S = 4S^(3)`
`S = ((K_(sp))/(4))^((1)/(3)) = ((32 xx 10^(-12))/(4))^((1)/(3)) = 2 xx 10^(-4) M`.


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