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The solubility product of `Ag CrO_(4)` is `32xx10^(-12).` What is the concentration of `CrO_(4)^(2-)` ions in that solution ?A. `2xx10^(-4)`B. `16xx10^(-4)`C. `8xx10^(-4)`D. `12xx10^(-4)` |
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Answer» Correct Answer - A `Ag_(2)CrO_(4)tounderset(2s)2Ag^(+)+underset(s)(CrO_(4)^(2-))` `K_(sp)=[Ag^(+)]^(2)[CrO_(4)^(2-)]` `=(2s)^(2)(s)` `K_(sp)=4s^(3)` `s=((K_(sp))/(4))^(1//3)` `=((32xx10^(-12))/(4))^(1//3)=2xx10^(-4)M` |
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