1.

The solubility product of BaSO_(4) at 18^(0) C is 1.5xx10^(-9) . It solubility (mole lit^(-1)) at the same temperature is

Answer»

`1.5 XX 10^(-9) `
` 1.5 xx 10^(-5)`
` 3.9 xx 10^(-9)`
` 3.9 xx 10^(-5)`

Solution :` K_(SP)=1.5 xx 10 ^(-9) `
`S = sqrt( K_(sp) ) = sqrt( 1.5 xx 10 ^(-9) )= 3.9 xx 10 ^(-5) M`


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