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1. |
The solubility product of `Hg_(2)I_(2)` is equal toA. `[Hg_(2)^(++)][I^(-)]`B. `[Hg^(++)][I^(-)]`C. `[Hg_(2)^(+)][I^(-)]^(2)`D. `[Hg^(++)][I^(-)]^(2)` |
Answer» Correct Answer - C is the correct answer. |
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