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The solubility product of Mg(OH)_(2) is 1.2 xx 10^(-11). The solubility of this compound in gram per 100 cm^(3) of solution is |
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Answer» `1.4 xx 10^(-4)` `K_(sp) = 4S^(3) rArr S = 3sqrt((K_(sp))/(4)) = 3sqrt((1.2 xx 10^(-11))/(4))` `S = 1.44 xx 10^(-4) mol L^(-1) = 58 xx 1.44 xx 10^(-4) g L^(-1)` (mol. mass of `Mg(OH)_(2) = 50`) `= 83.52 xx 10^(-4) g L^(-1) = 8.35 xx 10^(-4)g//100c C`. |
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