1.

The solubility product of silver chromate be K_(sp), its solubility is

Answer»

`root(3)(K_(sp ) //8)`
`root(3)(K_(sp))`
`root(3)(K_(sp)//4)`
`root(3)(K_(sp) //2)`

SOLUTION :`Ag_2 CrO _4 ` DISSOCIATES as
`Ag_2 CrO_4hArr2Ag^+ +CRO_(4)^(-)`
`K_(sp)=[AG^+] ^2[CrO_(4)^(-)]`
supposethe solubiltyof ` Ag_2 CrO_4`is Smol /litrethen
`K_(sp )= (2s)^2(s )= 4s^3`
` thereforeS=root(3) (K_(sp ) //4)`


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