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The solubility product of SrF_(2)in water is 8xx10^(-10) Calculate its solubility in 0.1 M of aqueous NaF solution. If its solubility is expressed as y xx 10^(-8)then what is the value of 'y' ? |
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Answer» ` [F^(-) ] " from " 0.1 M NAF " is "0.1 M` TOTAL ` [F^(-) ] =0.1 +2S = (0.1 )^(2) ` ` K_(sp)= S( 0.1) ^(2) rArr(8XX 10 ^(-10) )/( 10^(_2)) =SrArr S = 8 xx 10 ^(-8) ` |
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