1.

The solubility product of strontium fluoride is 8.0xx10^(-11). At what concentration of Sr^(2+)ion the precipitation of strontium fluoride would start from a solution containing 0.01 M F^(-) ion ?

Answer»

`8.xx10^(-9)M`
`8xx10^(-13)M`
`8.0xx10^(-7)M`
`1.25xx10^(-9)M`

Solution :`K_(SP)=[SR^(2+)][F^(-)]^(2)`
`[Sr^(2+)](0.01)^(2)=8.0xx10^(-11)`
`therefore [Sr^(2+)]=8.0xx10^(-7)M`


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