1.

The solubilityof PbSO_4 "in"0.01 M Na_2SO_4 solution is (K_(sp)of PbSO_4 is 1.25 xx 10^(-9) )

Answer»

` 1.25 XX 10 ^(-7) M`
` 1.25 xx 10^(-9) M`
` 1.25 xx 10^(-10) M`
` 0.1 M`

Solution :` PbSO_4 HARR Punderset(s) B^(+2)+ Sunderset( 0.01)Ooverset( 2-)`
` S( 0.01 )= 1.25 xx 10 ^(-9), S =1 .25 xx 10 ^(-7) `


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