1.

The solution containing 4g of KBr dissolved in 100 g of water freezes at - 1.24^(@)C. The molar mass of KBr is (K_(f) = 1.86 K kg "mol"^(-1)

Answer»

102
120
39
60

Solution :`M_(2) = i(K_(f) XX W_(2))/(Delta T_(f) xx W_(1)) xx 1000`
`= 2 xx (1.86 xx 4)/(1.24 xx 100) xx 1000 = 120`
`M_(2) "For" KBr = 39 + 80 = 119`


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