The solution for the equations c1x + b1y + a1 = 0 and c2x + b2y + a2 =

1.	The solution for the equations c1x + b1y + a1 = 0 and c2x + b2y + a2 = 0 is S1 : x = (b1a2–b2a1)(c1b2−c2b1) S2 : y = (c1a2–c2a1)(a1b2−a2b1)
Answer» The solution for the equations $c_{1}$ x + $b_{1}$ y + $a_{1}$ = 0 and $c_{2}$ x + $b_{2}$ y + $a_{2}$ = 0 is S1 : x = $\frac{(b_{1} a_{2} - b_{2} a_{1})}{(c_{1} b_{2} - c_{2} b_{1})}$ S2 : y = $\frac{(c_{1} a_{2} - c_{2} a_{1})}{(a_{1} b_{2} - a_{2} b_{1})}$

The solution for the equations c1x + b1y + a1 = 0 and c2x + b2y + a2 = 0 is S1 : x = (b1a2–b2a1)(c1b2−c2b1) S2 : y = (c1a2–c2a1)(a1b2−a2b1)

Answer»

The solution for the equations $c_{1}$ x + $b_{1}$ y + $a_{1}$ = 0 and $c_{2}$ x + $b_{2}$ y + $a_{2}$ = 0 is

S1 : x = $\frac{(b_{1} a_{2} - b_{2} a_{1})}{(c_{1} b_{2} - c_{2} b_{1})}$

S2 : y = $\frac{(c_{1} a_{2} - c_{2} a_{1})}{(a_{1} b_{2} - a_{2} b_{1})}$

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The solution for the equations c1x + b1y + a1 = 0 and c2x + b2y + a2 = 0 is S1 : x = (b1a2–b2a1)(c1b2−c2b1) S2 : y = (c1a2–c2a1)(a1b2−a2b1)

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