1.

The solution of (1 + y^(2)) dx = (Tan^(-1) y -x) dy is

Answer»

`X E^("Tan"^(-1)y)=(Tan^(-1)y-1)e^("Tan"^(-1)y)+C`
`x e^("Tan"^(-1)y)=("Tan"^(-1)y-1)e^("Tan"^(-1)y)-x+c`
`x=("Tan"^(-1)y-1)e^("Tan"^(-1)y)-y+c`
`x=("Tan"^(-1)y+1)e^("Tan"^(-1)y)-x+y+c`

Answer :4


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