1.

The solution of cos y log (sec x + tan x)dx = cos x log (sec y + tan y) dy is

Answer»

`[log (SEC x + TAN x)]^(2) - [log (sec y + Tany)^(2)] = c`
`[log (sec x + Tan x)]^(2) + [log (sec y + Tany)]^(2) = c`
`[log (sec x - Tan x)]^(2) - [log (sec y - Tany)]^(2) = c`
`[log (sec x - Tan x)]^(2) + [log (sec y + Tany)]^(2) = c`

ANSWER :A


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