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The solution of `CuSO_(4)` in which copper rod is immersed is diluted to times. The reduction electrode potentialA. increases by 29.5 m VB. decreases by 29.5 m VC. increases by 529 m VD. decreases by 592 m V |
Answer» Correct Answer - D A/C to Nernst equation `E = E^(@) + (0.0592)/(n) "log " [M^(n+)]` `[M^(n+)]` decreases by 100 times `therefore E = E^(@) + (0.0592)/(2) "log" (1)/(100) = E^(@) + (0.0592)/(2) "log" 10^(-2)` `E = E^(@) - (0.0592)/(2) xx 2 = E^(@) = -0.0592 V ` `E = E^(@) - 592` m V E decreases by 529 m V |
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